WebNov 13, 2012 · Technically, the char* is not an array, but a pointer to a char. Similarly, char** is a pointer to a char*. Making it a pointer to a pointer to a char. C and C++ both define arrays behind-the-scenes as pointer types, so yes, this structure, in all likelihood, is array of arrays of char s, or an array of strings. Share Improve this answer Follow WebC语言考试题及答案 D.! (a<=10)&&! (a>=15) (26) 若t为double类型,表达式t=1,t5,t++的值是 A.1 B.6.0 C.2.0 D.1.0 (27) 若有定义和语句: char s [10]:s="abcd";printf ("%s\n",s); 则结果是 (以下u代表空格) A.输出abcd B.输出a C.输出abcduuuuu for (i=5;i;i--) for (j=0;j<4;j++) {...} A.20 B.25 C.24 D.30 (33) 若有以下定义和语句: char *s1="12345",*s2="1234"; printf …
What’s difference between char s[] and char *s in C?
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若定义 char s[2][3]={"ab", "cd"}, *p=(char *)s; 那么下列表 …
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